A and B together can do a piece of work in 10 days. If A alone can do the work in 15 days, find in how many days that B alone can do the same work. The following are the steps involved in solving the above problem. Arrange them in sequential order.
One day's work of B is `(1)/(10)-(1)/(5)`.
One day's work of A and B is `(1)/(10)` and one day's work of A is `(1)/(15)`.
B alone can do the work in 30 days.
One day's work of B is `(1)/(30)`.