If `sec^4theta+sec^2theta=10+tan^4theta+tan^2theta,` then `sin^2theta=` `2/3` (b) `3/4` (c) `4/5` (d) `5/6`

If sec^(4) theta+ sec^(2) theta = 10 +tan^(4)theta + tan^(2) theta , then sin^(2) theta

Prove that sec^4theta-sec^2theta=tan^4theta+tan^2theta .

If sec^(4)theta+sec^(2)theta=10+tan^(4)theta+tan^(2)theta, then sin^(2)theta=(2)/(3)(b)(3)/(4)(c)(4)/(5)(d)(5)/(6)

x=a sec^(3)theta tan theta,y=b tan^(3)theta sec theta then sin^(2)theta=

x=a sec^(3)theta tan theta,y=b tan^(3)theta sec theta then sin^(2)theta

sec^(4) theta (1-sin^4 theta ) - tan^(2) theta =

sec^(4)theta-tan^(4)theta=sec^(2)theta+tan^(2)theta

Slove 4tan^2theta = 3sec^2theta

If sec^(4)theta-sec^(2)theta=3 then the value of tan^(4)theta+tan^(2)theta is:

Prove that tan^4theta+tan^2theta=sec^4theta-tan^2theta-1