Two particles are projected horizontally with same speed `30 m//s` but in opposite directions from same height at time `t = 0`. Calculate angle between velocity vectors of particles at time `t = 3s`.

A particle is projected horizontally with speed (20)/(sqrt(3))m//s , from some height at t=0. At what time its velocity will make 60^(@) angle with initial velocity ?

A particle is projected horizontally with speed (20)/(sqrt(3))m//s , from some height at t=0. At what time its velocity will make 60^(@) angle with initial velocity ?

Two particles are projected with speed 4 m//s and 3 m//s simultaneously from same point as shown in the figure. Then :

Two particles are projected with speed 4m//s and 3m//s simultaneously from same point as shown in the figure. Then:

Two particles are projected with speed 4m//s and 3m//s simultaneously from same point as shown in the figure. Then:

A particle is projected horizontally with a speed of (40)/(sqrt3)m//s , from some height t = 0 . At what time its velocity makes 60^(@) angle with initial velocity. (g=10m//s^(2))

A particle is projected at an angle of 30^(@)w.r.t. horizontal with speed 20m//s:( use g=10m//s^(2)) (i) Find the position vector of the particle after 1s . (ii) Find the angle between velocity vector and position vector at t=1s .

A particle is projected at an angle of 30^(@)w.r.t. horizontal with speed 20m//s:( use g=10m//s^(2)) (i) Find the position vector of the particle after 1s . (ii) Find the angle between velocity vector and position vector at t=1s .

Two particles are projected from a tower horizontally in opposite directions with velocities 10 m//s and 20 m//s . Find the time when their velocity vectors are mutually perpendicular. Take g=10m//s^2 .