If `f(n) = [(1)/(3)+(n)/(100)]`, where `[.]` denotes `G.I.F` then `sum_(n=1)^(200)f(n)` is equal to

where f (n) = [(1)/(3) + (3n)/(100)] n, where [ n] denotes the greatest integer less than or equal to n. Then sum_(n=1)^(56)int (n) is equal to :

Let f(n)= [(1)/(3) + (3n)/(100)]n , where [n] denotes the greatest integer less than or equal to n. Then Sigma_(n=1)^(56) f(n) is equal to

Let f(n) = [(1)/(2) + (n)/(100)] where [n] denotes the integral part of n. Then the value of sum_(n=1)^(100) f(n) is

Let f(n)=[(1)/(2)+(n)/(100)] where [x] denote the integral part of x. Then the value of sum_(n=1)^(100)f(n) is

Let f(n) = [1/2 + n/100] where [x] denote the integral part of x. Then the value of sum_(n=1)^100 f(n) is

Let f(n)=[1/2+n/100] where [x] denote the integral part of x. Then the value of sum_(n=1)^100f(n) is

Let f(n)=[(1)/(2)+(n)/(100)] where I 1 denotes the greatest integer function,then the value of sum_(n=1)^(151)f(n) is