The area bounded by `4x^2 le y le 8x+12` is -

Find the area bounded by the curves x ^(2) le y le x + 2:

The area bounded by y=x^(2), y=sqrt(x), 0 le x le 4 is

The area bounded by the curve y = sin x, pi le x le 2 pi and the x-axis is

The area bounded by y=x^(2),y=[x+1], 0 le x le 2 and the y-axis is where [.] is greatest integer function.

The area bounded by y=x^(2),y=[x+1], 0 le x le 2 and the y-axis is where [.] is greatest integer function.

The area bounded by y=x^(2),y=[x+1], 0 le x le 2 and the y-axis is where [.] is greatest integer function.

The area bounded by y=x^(2),y=[x+1], 0 le x le 2 and the y-axis is where [.] is greatest integer function.

The area ( in Sq. units ) of the region {(x ,y) in R |4x^2 le y le 8x + 12} is :

The area bounded by the y-axis, y = cos x and y = sin x, 0 le x le pi/4 is

Find the area bounded by y = sin x, 0 le x le (pi)/(4), y= cos x, (pi)/(4) le x le (pi)/(2) and the x-axis