If the focus of the parabola is `(-2,1)` and the directrix has the equation `x+y=3` then the vertex is

If the focus of a parabola is (-2,1) and the directrix has the equation x+y=3 then its vertex is a. (0,3) b. (-1,1/2) c. (-1,2) d. (2,-1)

If the focus of a parabola is (-2,1) and the directrix has the equation x+y=3 then its vertex is a.(0,3) b.(-1,1/2) c.(-1,2) d.(2,-1)

The vertex of a parabola is (a,0) and the directrix is x+y=3a the equation of the parabola is

The vertex of a parabola is (a,0) and the directrix is x+y=3a. The equation of the parabola is

The focus of the parabola whose vertex is (3,2) and directrix is x-y+1=0 is -

Find the equation of the parabola with vertex is (2, 1) and the directrix is x = y -1.

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1 .

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

FInd the equation of the parabola The focus at (1,1) the directrix x-y=3