In `Delta ABC, if sin A cos B=1//4 and 3 tan A=tan B`, the triangle is right angled at

In a !ABC if sin A cos B = 1/4 and 3 tan A = B , then the triangle is

If sin A cos B = (1)/(4) and 3 tan A = tan B then triangle is

In a triangle ABC if sin A cos B = 1/4 and 3 tan A = tan B , then the triangle is

in a Delta ABC,3sin A+4cos B=6 and 3cos A+4sin B=1 then angle C is

In Delta ABC If cos A cos B cos C=(1)/(3) then tan A tan B+tan B tan C+tan C tan A=

In a Delta ABC, if cos A cos B cos C=(1)/(3) then value of,tan A tan B+tan B tan C+tan C tan A is

In any triangle ABC, if cosA cos B + sin A sin B sinC =1 then prove that the triangle in an isosceles right angled.

In Delta ABC, if tanA: tan B: tan C=1:2:3 , then sin A: sin B: sin C =