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If one zero of the quadratic polynomial ...

If one zero of the quadratic polynomial `kx^(2) + 3x+k` is 2 then the value of k is

A

`5/6`

B

` (-5)/6`

C

` 6/5`

D

`(-6)/5`

Text Solution

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The correct Answer is:
To find the value of \( k \) in the quadratic polynomial \( kx^2 + 3x + k \) given that one zero is 2, we can follow these steps: ### Step 1: Substitute the known zero into the polynomial Since one zero is 2, we can substitute \( x = 2 \) into the polynomial: \[ k(2^2) + 3(2) + k = 0 \] This simplifies to: \[ 4k + 6 + k = 0 \] ### Step 2: Combine like terms Combine the \( k \) terms: \[ 5k + 6 = 0 \] ### Step 3: Solve for \( k \) Now, isolate \( k \): \[ 5k = -6 \] \[ k = -\frac{6}{5} \] ### Final Answer Thus, the value of \( k \) is: \[ k = -\frac{6}{5} \] ---
To find the value of \( k \) in the quadratic polynomial \( kx^2 + 3x + k \) given that one zero is 2, we can follow these steps: ### Step 1: Substitute the known zero into the polynomial Since one zero is 2, we can substitute \( x = 2 \) into the polynomial: \[ k(2^2) + 3(2) + k = 0 \] This simplifies to: ...
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