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Evaluate: (cos 58^@)/(sin 32^@)+(sin ...

Evaluate:
` (cos 58^@)/(sin 32^@)+(sin 22^@)/(cos 68^@)-(cos 38^@cosec 52^@)/(tan 18^@tan 35 ^@ tan 60^@tan 72^@tan 55^@)`.

A

`(1)/(3)(6-sqrt(3))`

B

`(2)/(3)(6-sqrt(3))`

C

`(1)/(3)(3-sqrt(6))`

D

`(2)/(3)(3-sqrt(6))`

Text Solution

AI Generated Solution

The correct Answer is:
To evaluate the expression \[ \frac{\cos 58^\circ}{\sin 32^\circ} + \frac{\sin 22^\circ}{\cos 68^\circ} - \frac{\cos 38^\circ \cdot \csc 52^\circ}{\tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ}, \] we will simplify each term step by step. ### Step 1: Simplifying the first term We know that \[ \cos 58^\circ = \sin(90^\circ - 58^\circ) = \sin 32^\circ. \] Thus, we can rewrite the first term: \[ \frac{\cos 58^\circ}{\sin 32^\circ} = \frac{\sin 32^\circ}{\sin 32^\circ} = 1. \] ### Step 2: Simplifying the second term Next, we simplify the second term: \[ \cos 68^\circ = \sin(90^\circ - 68^\circ) = \sin 22^\circ. \] So, we can rewrite the second term: \[ \frac{\sin 22^\circ}{\cos 68^\circ} = \frac{\sin 22^\circ}{\sin 22^\circ} = 1. \] ### Step 3: Simplifying the third term Now, we simplify the third term: \[ \csc 52^\circ = \frac{1}{\sin 52^\circ}. \] Also, we know that \[ \cos 38^\circ = \sin(90^\circ - 38^\circ) = \sin 52^\circ. \] Thus, we can rewrite the third term: \[ \frac{\cos 38^\circ \cdot \csc 52^\circ}{\tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ} = \frac{\sin 52^\circ \cdot \frac{1}{\sin 52^\circ}}{\tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ} = \frac{1}{\tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ}. \] ### Step 4: Evaluating the product of tangents The product of tangents can be simplified using the identity: \[ \tan(90^\circ - x) = \cot x. \] Thus, we have: \[ \tan 72^\circ = \cot 18^\circ, \quad \tan 60^\circ = \sqrt{3}, \quad \tan 55^\circ = \cot 35^\circ. \] So, the product becomes: \[ \tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ = \tan 18^\circ \tan 35^\circ \cdot \sqrt{3} \cdot \cot 18^\circ \cdot \cot 35^\circ = \sqrt{3}. \] ### Step 5: Final expression Now we can combine everything: \[ 1 + 1 - \frac{1}{\sqrt{3}} = 2 - \frac{1}{\sqrt{3}}. \] To express this in a single fraction, we can write: \[ 2 = \frac{2\sqrt{3}}{\sqrt{3}}. \] Thus, the final expression becomes: \[ \frac{2\sqrt{3} - 1}{\sqrt{3}}. \] ### Final Answer The evaluated expression is: \[ \frac{2\sqrt{3} - 1}{\sqrt{3}}. \] ---

To evaluate the expression \[ \frac{\cos 58^\circ}{\sin 32^\circ} + \frac{\sin 22^\circ}{\cos 68^\circ} - \frac{\cos 38^\circ \cdot \csc 52^\circ}{\tan 18^\circ \tan 35^\circ \tan 60^\circ \tan 72^\circ \tan 55^\circ}, \] we will simplify each term step by step. ...
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