The cartesian equation of a line is ` 3x + 1 = 6 y - 2 = 1 -z`.
Find the vector equation of the line.

The cartesian equation of a line is 3x - 1 = 6y + 2 = 1 - z . Find the vector equation of the line .

The cartesian equation of a line is 6x - 2 = 3y + 1 = 2z - 2 . Find :(a) the direction-ratios of the line, and (b) vector equation of the line parallel to this line and· passing through the point (2, - 1, - 1).

The cartesian equation of a line is (x - 6) /(2) = ( y + 4)/(7) = (z -5)/(3) , find its vector equation .

The equation of line is 2x - 2 = 3y + 1 = 6z - 2 find its direction ratios and also find the vector equation of the line .

The cartesian equations of line is : (x - 1)/(2) = (y - 2)/(3) = (z -3)/(4) . Write the vector equation.

The cartesian equations of a line is 6x - 2 = 3y + 1 = 2z - 2. Find the direction cosines of the line. Write down the cartesian and vector equations of a line passing through the point (2-1, -1) which are-parallel to the given line.

The cartesian equation of a line are 6x - 2 = 3y + 1 = 2z - 2. Find its vector equation.

The Cartesian equation of a line is (x+3)/2 = (y-5)/4 = (z+6)/2 . Find the vector equation for the line.

The cartesian equations of a line are 3x + 1 = 6y - 2 = 1 - z. Find the fixed point through which it passes, its direction ratios and also its vector equation.