The length of a bar magnet is 10 cm and its pole strength is `10^(-3)` Weber. It is placed in a magnetic field of induction `4 pi × 10^(-3)` Tesla in a direction making an angle `30^(@)` with the field direction. The value of torque acting on the magnet will be –

A bar magnet of length 10cm and having the pole strength equal to 10^(-3) weber is kept in a magnetic field having magnetic induction (B) equal to 4pixx10^(-3) Tesla. It makes an angle of 30^(@) with the direction of mwgnetic induction. The value of the torque acting on the magnet is (mu_(0)=4pixx10^(-7) weber//ampxxm)

A magnet of length 10 cm and pole strength 4xx10^(-4)Am is placed in a manetic field of induction 2xx10^(-5)weber m^(-2) , such that the axis of the magnet makes an angel 30^(0) with the lines of induction. The moment of the couple acting on the magnet is

A bar magnet of pole strength 2 A-m is kept in a magnetic field of induction 4xx10^(-5) Wbm^(-2) such that the axis of the magnet makes an angle 30^(@) with the direction of the field. The couple acting on the magnet is found to be 80xx10^(-7) N-m. Then, the distance between the poles of the magnet is

A bar magnet of length 10cm and pole strength 2 Am makes an angle 60^(0) with a uniform magnetic field of induction 50T . The couple acting on it is

A bar magnet of length 10cm and pole strength 2 Am makes an angle 60^(0) with a uniform magnetic field of induction 50T . The couple acting on it is

A bar magnet of length 0.2 m and pole strength 5 Am is kept in a uniform magnetic induction field of strength 15 wb//m^(-2) making an angle of 30^(@) with the field. Find the couple acting on it.