The distance form a fixed point `O` of a particle pmoving in a straight line from `O` is given by `s=16+48t-t^3`. The direction of motion of the particle after `t=4` sec is

The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

The displacement x of a particle in a straight line motion is given by x=1-t-t^(2) . The correct representation of the motion is

The displacement x of a particle in a straight line motion is given by x=1-t-t^(2) . The correct representation of the motion is

Position of a particle moving in a straight line is given as y = 3t^3 + t^2 (y in cm and t in second) then find acceleration of particle at t = 2sec

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "

The distance S metres moved by a particle traveling in a straight line in t second is given by S = 45t +11t^2-t^3 . Find the time when the particle comes to rest.

Distance covered by a particle moving in a straight line from origin in time t is given by x = t- 6t^(2)+t^(3) . For what value of t, will the particle's acceleration be zero?

A particle 'p' moves along a straight line away from a point 'O' obeying the relation S = 16 + 48t - t^(3) . The direction of 'P' after t = 4 is

The distance s meters moved by a particle travelling in a straight line t seconds is given by s = 45t + 11t^(2) - t^(3) . Find the acceleration when the particle comes to rest.