A particle is located at (3m , 4m) and moving with `v=(4hati-3hatj)m//s`. Find its angular velocity about origin at this instant.

A particle is projected from ground with velocity 3hati + 4hatj m/s. Find range of the projectile :-

A particle is projected from ground with velocity 3hati + 4hati m/s. Find range of the projectile :-

A particle starts from the point (0m, 8m) and moves with uniform velocity of 3 hat i m//s . After 5 seconds, the angular velocity of the particle about the origin will be : .

A particle starts from the point (0m, 8m) and moves with uniform velocity of 3 hat i m//s . After 5 seconds, the angular velocity of the particle about the origin will be : .

A particle is projected from ground with initial velocity 3hati + 4hatj m/s. Find range of the projectile :-

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

A particle is moving in x-y plane. Its initial velocity and acceleration are u=(4 hati+8 hatj) m//s and a=(2 hati-4 hatj) m//s^2. Find (a) the time when the particle will cross the x-axis. (b) x-coordinate of particle at this instant. (c) velocity of the particle at this instant. Initial coordinates of particle are (4m,10m).

A particle is moving in x-y plane. Its initial velocity and acceleration are u=(4 hati+8 hatj) m//s and a=(2 hati-4 hatj) m//s^2. Find (a) the time when the particle will cross the x-axis. (b) x-coordinate of particle at this instant. (c) velocity of the particle at this instant. Initial coordinates of particle are (4m,10m).