Two resistors of resistance `R_(1)` and `R_(2)` having `R_(1) gt R_(2)` are connected in parallel. For equivalent resistance R, the correct statement is

Two resistors of resistance R_1 and R_2 having R_1>R_2 are connected in parallel. For equivalent resistance R, the correct statement is

Two resistance R1 and R2 connected in parallel, this equivalent resistance is.

Four resistors R_(1) , R_(2) , R_(3) and R_(4) are connected in parallel . The resultant resistance R is

Two resistor of resistance R_(1)=(6+-0.09)Omega and R_(2)=(3+-0.09)Omega are connected in parallel the equivalent resistance R with error (in Omega)

Two resistor of resistance R_(1)=(6+-0.09)Omega and R_(2)=(3+-0.09)Omega are connected in parallel the equivalent resistance R with error (in Omega)

If resistors of resistance R_(1) and R_(2) are connected in parallel,then resultant resistance is "

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

Three resistors R_1, R_2, and R_3 , and are connected in parallel. Find out equivalent resistance of combination.