[" At a height of "15m" from ground velocity of a projectile is "v=(10hat i+10hat j)" .Here,i is "],[" upwards and "hat i" is along horizontal direction,then (Take,"g=10ms^(-2)" ) "]

At a height of 15 m from ground velocity of a projectile is v = (10hati+ 10hatj) . Here hatj is vertically upwards and hati is along horizontal direction then (g = 10 ms^(-1) )

At a height of 15 m from ground velocity of a projectile is v = (10hati+ 10hatj) . Here hatj is vertically upwards and hati is along horizontal direction then (g = 10 ms^(-1) )

At a height 0.4 m from the ground the velocity of a projectile in vector form is vec v = (6 hat i+ 2 hat j) ms ^-1 . The angle of projection is

At a height 0.4 m from the ground the velocity of a projectile in vector form is vec v = (6 hat i+ 2 hat j) ms ^-1 . The angle of projection is

At a height of 0.4 m from the ground, the velocity of projectile in vector from is vec(u)=(6hat(i)+2hat(j)) (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is : (g = 10 m//s^(2))

A ball of mass 2 kg is thrown from a tall building with velocity, v=(20 m//s)hat(i)+(24 m//s) hat(j) at time t=0 s. Change in the potential energy of the ball after, t=8 s is (The ball is assumed to be in air buring its motion between 0 s and 8 s, hat(i) is along the horizontal and hat(j) is along the vertical direction. (Take g=10 m//s^(2) )

A body is projected from the ground with a velocity vec(v)= (3 hat(i) + 10 hat(j)) ms^(-1) . The maximum height attained and the range of the body respectively are (given g= 10 ms^(-2) )

The initial velocity of a projectile at the point of projection is 3hat i+4hat j ms^(-1) .Then the velocity of striking on the ground is

" A projectile is given an initial velocity "hat i+2hat j" .The cartesian equation of its path is "[" take "g=10m/s^(2)]

A ball is thrown with an initialy velocity (a hat(i) + b hat(j)) m//s from ground. Here we have choose y-axis along vertical and x-axis along horizontal direction. If the range of projectile is half the maximum height, then b//a is :