int(dx)/(sqrt((x-alpha)(beta-x))),beta>alpha

int (dx)/(sqrt((x-alpha)(x-beta)))

Evaluate : int(dx)/((x-alpha)(beta-x))beta gt alpha

Integrate : int (dx)/(sqrt((x-alpha)(beta-x)))[ alpha lt x lt beta]

Evaluate: int(1)/((x-alpha)(beta-x))dx,(beta>alpha)

int(dx)/(sin(x-alpha)sin(x-beta))

Evaluate: int_(alpha)^(beta)(dx)/(sqrt((x-alpha)(beta-x)))dx

int(dx)/(sin(x-alpha)sin(x-beta)

Evaluate: int1/((x-alpha)(beta-x))dx ,(beta>alpha)

Evaluate: int1/((x-alpha)(beta-x))dx ,(beta>alpha)

Putting x=alphacos^(2)theta+betasin^(2)theta show that, int_(alpha)^(beta)sqrt((x-alpha)(beta-x))dx=((beta-alpha)^(2)pi)/(8)