Consider the differential equation `y^2 dx + (x+1/y)dy =0`. If `y(1) =1`, then x is given by: (A) `1-1/y +(1/e^y)/e` (B) `4-2/y -(e^y)/e` (C) `3-1/y +(e^y)/e` (D) `1+1/y- (1/e^y)/e`

Consider the differential equation y^(2)dx+(x+(1)/(y))dy=0. If y(1)=1, then x is given by: (A) 1-(1)/(y)+((1)/(e^(j)))/(e)(B)4-(2)/(y)-(e^(y))/(e)(C)3-(1)/(y)+(e^(y))/(e)(D)1+(1)/(y)-((1)/(e^(y)))/(e)

Solution of the differential equation (1+e^(x/y))dx + e^(x/y)(1-x/y)dy=0 is

Solution of the differential equation (1+e^(x/y))dx + e^(x/y)(1-x/y)dy=0 is

The differential equation (e^(x)+1)y dy = (y+1) e^(x) dx has the solution

Solve the differential equation e^(x) tan y dx + (1-e^(x))sec^(2) y dy = 0

Solve the following differential equation: y(1+e^(x))dy=(y+1)e^(x)dx

The solution of the differential equation x(e^(2y)-1)dy + (x^2-1) e^y dx=0 is

The solution of the differential equation x(e^(2y)-1)dy + (x^2-1) e^y dx=0 is