A block off mass 200 g executing SHM under the unfluence of a spring of spring constant `k=90Nm^(-1)` and a damping constant `gb=40gs^(-1)`. The time elaspsed for its amplitude to drop to halff of its initial value is (Given, ln `(1//2)=-0.693`)

A block of mass 200 g executing SHM under the influence of a spring of spring constant k=90Nm^(-1) and a damping constant b=40gs^(-1) . The time elapsed for its amplitude to drop to half of its initial value is (Given, ln (1//2)=-0.693 )

For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^(-1) and the damping constant b is 40 gs^(-1) . Calculate time taken for its amplitude of vibrations to drop to half of its initial value.

For the damped oscillator, the mass m of the block is 400g, k = 120 Nm^(-1) and the damping constant b is 50 gs^(-1) . Calculate time taken for its amplitude of vibration to drop to half of the initial value.

In damped oscillatory motion a block of mass 20kg is suspended to a spring of force constant 90N//m in a medium and damping constant is 40g//s . Find (a) time period of oscillation (b) time taken for amplitude of oscillation to drop to half of its intial value (c) time taken for its mechanical energy to drop to half of its initial value.

For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^(-1) and the damping constant b is 40 gs^(-1) . Calculate the time taken for its mechanical energy to drop to half its initial value.