`I=int_(0)^(2)x sqrt(x+2)dx`

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int_(0)^(2) sqrt(2-x)dx .

I=int_(0)^(2)x sqrt(4-x^(2))dx

int_(0)^(2)x^(2)sqrt(2-x)dx

int_(0)^(1)x sqrt(x^(2)+2)dx

int_(0)^(2)(1)/(sqrt(x))dx

int_(0)^(sqrt(2))[x^(2)]dx

Compute the integrals I = int_(0)^(2a) sqrt(2 a x - x^(2)) dx

- int_(4)^(0)(sqrt(x)-2)dx

int_(0)^(2)x^(2)sqrt(4-x^(2))dx=