Consider `f: R _(+) to [-5, oo)` given by `f (x) = 9x ^(2) + 6x -5.` Show that f is invertible with `f ^(-1) (y) = ((sqrt(y +6) -1)/(3)).`

Consider f: R _(+_ to [4, oo) given by f (x) = x ^(2) + 4. Show that f is invertible with the inverse f ^(-1) given by f ^(-1) (y) = sqrt (y -4), where R _(+) is the set of all non-negative real numbers.

f : R to (0, oo) defined by f (x) = 2 ^(x) . then f ^-1(x)

f : R to (0, oo) defined by f (x) = 5 ^(x). then f ^-1(x)

If f: [1, oo) rarr [5, oo) is given by f(x) = 3x + (2)/(x) , then f^(-1) (x) =

f : R to (0, oo) defined by f (x) = log _(2) (x). then f ^-1(x)

If f : R to R is defined by f(x) = x^(2)- 6x + 4 then , f(3x + 4) =

f: R to R is defined by f(x) =x^(2)-5x . Then the inverse image set of {-6} is

If f(x) =x^4 + 3x ^2 - 6x -2 then the coefficient of x^3 in f(x +1) is