p(x) =x +2. Find p(1), p (2),p (-1) and ...

`p(x) =x +2.` Find `p(1), p (2),p (-1) and p (-2).` Which among `1,2,-1 and -2` becomes the 0 of `p (x)` ?

Verified by Experts

The correct Answer is:

`-2`

Similar Questions

Explore conceptually related problems

Find p (1), p (2) and p (3) for the polynomial p (x) = (x-1) (x+1)

Find p (0), p (1) and p (2) for the polynomials p (y) =y ^(2) - y + 1

P(9,2) = P(x,2).Find x.

Find p (0), p (1) and p (2) for the polynomials p (t) = 2 +1 + 2t^2 -t^3

Find p (0) p, (1) and p (2) for the following polynomials. p (x) = x ^(2) - x +1

Let p(x)=x^(2)-4x+3 . Find the value of p(0),p(1),p(2),p(3) and obtain zeroes of the polynomial p(x) .

The points (p+1,1), (2p+1,3) and (2p+2, 2p) are collinear, if

If p(x)=x^(2)-5x-6 , then find the values of p(1),p(2),p(3),p(0),p(-1),p(-2),p(-3) .

If p(x + 1) = x + 4, then find the value of [p(1) + p(-1)] is

The quadratic polynomial p(x) has the following properties: p(x)geq0 for all real numbers, p(1)=0 and p(2)=2 . Find the value of p(3) is__________.