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Faactorise (i) 27a ^(3) + 64 b ^(3)...

Faactorise
(i) `27a ^(3) + 64 b ^(3)`

Text Solution

Verified by Experts

The correct Answer is:
(i) `(3a + 4b) (9a^(2) -12ab+ 16 b ^(2)) `
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Fractorise a ^(3) - 8b ^(3) - 64 c^(3) - 24 abc

Factorise 27a ^(3) + b ^(3) + 8c^(3) -18 abc using identity.

Factorise : a^(6)+32a^(3)-64

Factorise:- (27x^3 - 64y^3)

Factorise : x^(3)+y^(3)-12xy+64

Let's factorise (27a^3 - 64) with the help of the identity.

Factorise : 2sqrt(2)a^(3)+8b^(3)-27c^(3)+18sqrt(2)abc

Factorise : a^(3)+(1)/(a^(3))+(26)/(27)

Factorise : x^(3)+(1)/(x^(3))+(47)/(64)

Let’s mark '√' the correct answer - (i) How many 1/16 are there in 3/4 (a) 64 (b) 12 (c ) 64m (d) 3