In the adjacent figure PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflected back along CD . Prove that AB || CD.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

Two plane mirrors are inclined to each other at an angle theta .A ray of light is reflected first at one mirror and then at the other . The total deviation of the ray is

Two circle intersect each other at A and B and a straight line parallel to AB intersects the circles at C,D,E,F. Prove that CD = EF.

A ray of light is reflected by a plane mirror. hatepsilon_(0), hate and hatn be the unit vectors along the incident ray, reflected ray and the normal to the reflecting surface respectively. Which of the following gives an expression for hate ?

A ray of light travelling along the line 2x-3y+5=0 ,after striking a plane mirror lying along the line x+y-2=0 gets reflected then equation of the reflected straight line is

A triangle ABC has vertices A(5, 1), B (-1, -7) and C(1, 4) respectively. L be the line mirror passing through C and parallel to AB and a light ray eliminating from point A goes along the direction of internal bisector of the angle A, which meets the mirror and BC at E, D respectively. If sum of the areas of triangle ACE and triangle ABE is K sq units then (2K)/5-6 is

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is (a) x=0 (b) x=2 (c) x+y (d) 2x+y=4

Two two circle with their centre at P and Q intersect each other, at the point A and B . Through the point A , a straight line parallel to PQ intersects the two circles at the points C and D respectively . If PQ = 5 cm , then determine the lenght of CD .

A ray of light is incident on a concave mirror along its principal axis.What will be the angle of reflection?