In quadrilateral ABCD, AB = CD, BC=AD show that `DeltaABC ~= DeltaCDA` Consider `DeltaABC and DeltaCDA`

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the the cyclic quadrilateral ABCD,AB =CD . Prove that AC= BC

In quadrilateral ACBD, AC = AD and AB bisects /_A Show that DeltaABC~= DeltaABD . What can you say about BC and BD?

If in the cyclic quadrilateral AB||CD , then prove that AD =BC and AC=BD.

In the quadrilateral ABCD , AD = BC and angleBAD = angleABC . Prove that the quadrilateral is an isosceles trapezium.

In a quadrillateral ABCD, it is given that AB ||CD and the diagonals AC and BD are perpendiclar to each other . Show that AD. BC = AB. CD.

In DeltaABC,AB = BC = 6.5 cm and angleABC= 60^(@) . Construct the DeltaABC

Line AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that (i) Delta AOD ~= DeltaBOC and (ii) AD || BC .

A cyclic quadrilateral ABCD is such that AB = BC, AD = DC, AC bot BD , angleCAD = theta , then the angle angleABC equals___

DeltaABC and DeltaBDE are two equilateral triangles. If D is the mid-point of BC , then the ratio of the areas of DeltaABC and DeltaBDE is