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Look at the following pattern : (i) 28...

Look at the following pattern :
(i) `28 = 2^(2) xx 7^1` , Total number of factors (2+1) (1+1)=` 3 xx 2 =6`
28 is divisible by 6 factors i.e., 1,2,4,7,14,28
(ii) ` 30=2^(1) xx 3^(1) xx 5^(1)` , Total number of factors `( 1+1)(1+1)(1+1)=2 xx 2 xx 2 =8`
30 is divisible by 8 factor i.e., 1,2,3,5,6,10,15,30 find pattern

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