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CD and GH are respectively the bisectors...

CD and GH are respectively the bisectors of `angle ACB and angle EGF` such that D and H lie on sides AB and FE of `Delta ABC and Delta FEG` respectively. If `Delta ABC ~ Delta FEG`, then show that
(i) `(CD)/(GH) = (AC)/(FG)` (ii) `Delta DCB ~ Delta HGE ` (iii) ` Delta DCA ~ Delta HGF`

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