The coefficients of three consecutive terms in the expansion of `(1 + a)^n` are are in the ratio 1: 7: 42 Find n.

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

The three successive of the consecutive three terms in the expansion of (1+x)^(n) are in the ratio 1 : 2 : 3 . Find n .

The coefficient of the middle term in the expansion of (1+x)^(2n) is

The coefficient of the middle term of the expansion of (1-2x+x^2)^n is

The coefficients of 5th ,6th and 7th terms in the expansion of (1+x)^(n) are A.P . ,find n .

The coefficient of three consecutive terms in the expansion of (1+x)^n are a, b, c respectively prove that (2ac+b(a+c))/(b^2-ac)=n .

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ration 5 : 10 : 14 . Then n =

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ratio 5 : 10 : 14. Then n= _______

If the coefficients if three successive terms in the expansion of (1+x)^(n) are 120 ,210 and 252 respectively . Find n .

If the coefficient of 4th term in the expansion of (a+b)^n is 56, then n is