Find the value of (a^2 + sqrta^2 - 1)^4 ...

Find the value of (`a^2 + sqrta^2 - 1)^4` + `(a^2 - sqrt'a^2 - 1')^4` .

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The correct Answer is:

`2a^8` + `12a^6` - `10a^4` -`4a^2` + 2

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