Home
Class 11
MATHS
The first term of a G.P. is 1. The sum o...

The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.

Text Solution

Verified by Experts

The correct Answer is:
`pm3`
Promotional Banner

Topper's Solved these Questions

  • SEQUENCES AND SERIES

    NCERT BANGLISH|Exercise EXERCISE 9.4|10 Videos
  • RELATIONS AND FUNCTIONS

    NCERT BANGLISH|Exercise Miscellaneous Exercise on Chapter 2|12 Videos
  • SETS

    NCERT BANGLISH|Exercise MISCELLANEOUS EXERCISE ON CHAPTER 1|26 Videos

Similar Questions

Explore conceptually related problems

The first terms of a G.P. is 1. The sum of the third and fifth terms is 90. Find the common ratio of the G.P.

The sum of first 8 terms of a G.P. is five times the sum of the first 4 terms. Find the common ratio.

The sum of first 6 terms of a G.P. is 9 times the sum of its first 3 terms. Find the common ratio of the G.P.

If the 3rd term of a G.P. is the square of the first term and its fifth term is 729, find the G.P.

The sum of infinite number of terms in G.P. is 20 and the sum of their squares is 100. Then find the common ratio of G.P.

The sum of first ten terms of an A.P. is 155 and the sum of first two terms of a G.P. is 9. The first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to the common difference of the A.P. Find the two progressions.

If each term of an infinite G.P. is twice the sum of the terms following it, then find the common ratio of the G.P.

The sum of the first p terms of an A.P. is q and the sum of the first q terms of the same A.P. is p. Find the sum of the first (p+q) terms of the A.P.

The sum of first three terms of a G.P. is 39/10 and their product is 1. Find the common ratio and the terms.

The sum of first three terms of a G.P. is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.

NCERT BANGLISH-SEQUENCES AND SERIES-Miscellaneous Exercise On Chapter 9
  1. If f is a function satisfying f (x +y) = f(x) f(y) for all x, y in N ...

    Text Solution

    |

  2. The sum of some terms of G.P. is 315 whose first term and the common r...

    Text Solution

    |

  3. The first term of a G.P. is 1. The sum of the third term and fifth ter...

    Text Solution

    |

  4. The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from t...

    Text Solution

    |

  5. A G.P. consists of an even number of terms. If the sum of all the term...

    Text Solution

    |

  6. The sum of the first four terms of an A.P. is 56. The sum of the last ...

    Text Solution

    |

  7. If (a+bx)/(a-bx)=(b+cx)/(b-cx)=(c+dx)/(c-dx)( x ne 0) then show that ...

    Text Solution

    |

  8. Let S be the sum, P the product and R the sum of reciprocals of n term...

    Text Solution

    |

  9. The p^(th), q^(th) and r^(th) terms of an A.P. are a, b, c, respectiv...

    Text Solution

    |

  10. If a(1/b+1/c),b(1/c+1/a),c(1/a+1/b) are in A.P., prove that a,b,c are...

    Text Solution

    |

  11. If a, b, c, d are in G.P, prove that (a^n + b^n), (b^n + c^n), (c^n +...

    Text Solution

    |

  12. If a and b are the roots of x^2 – 3x + p = 0 and c, d are roots of x^...

    Text Solution

    |

  13. The ratio of the A.M. and G.M. of two positive numbers a and b, is m :...

    Text Solution

    |

  14. If a, b, c are in A.P., b, c, d are in G.P. and 1/c,1/d,1/e are in A.P...

    Text Solution

    |

  15. Find the sum of the following series up to n terms: 5+55+555+......

    Text Solution

    |

  16. Find the 20^(th) term of the series 2 xx 4 + 4 xx 6 + 6 xx 8 + ... + ...

    Text Solution

    |

  17. Find the sum of the first n terms of the series: 3+ 7 +13 +21 +31 +......

    Text Solution

    |

  18. If S1, S2, S3 are the sum of first n natural numbers, their squares a...

    Text Solution

    |

  19. Find the sum of the following series up to n terms: 1^3/1+(1^3+2^3)/...

    Text Solution

    |

  20. Show that (1xx2^2+2xx3^2+...+nxx(nxx1)^2)/(1^2xx2+2^2xx3+...+n^2xx(n+1...

    Text Solution

    |