Home
Class 12
MATHS
y = Ax : xy' = y (x ne 0)...

`y = Ax : xy' = y (x ne 0)`

Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIAL EQUATIONS

    NCERT BANGLISH|Exercise EXERCISE - 9.3|12 Videos
  • DIFFERENTIAL EQUATIONS

    NCERT BANGLISH|Exercise EXERCISE - 9.4|23 Videos
  • DIFFERENTIAL EQUATIONS

    NCERT BANGLISH|Exercise EXERCISE - 9.1|12 Videos
  • DETERMINANTS

    NCERT BANGLISH|Exercise Miscellaneous Exercises on Chapter 4|18 Videos
  • INTEGRALS

    NCERT BANGLISH|Exercise EXERCISE 7.12|44 Videos

Similar Questions

Explore conceptually related problems

y = x sin x : xy' = y + x sqrt(x^(2) - y^(2))(x ne 0 and x gt y or x lt -y)

Solve x(dy)/(dx) + y + xy cot x = 0 (x ne 0)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

y = sqrt(a^(2) - x^(2)) x ne (-a, a) : x + y (dy)/(dx) = 0(y ne 0)

Solve the differential equation y dx = (x + y^(2))dy ( y ne 0) .

Let's add : 4xy + 5x + 7y, - 4xy - y - 3x, 3xy - 3y + 2x

if y + x = 5xy , y - x = -xy

Solve the following simultaneous linear equations in two variables by the method of elimination : (x+y)/(xy)=2, (x-y)/(xy)=1, (x ne 0, y ne 0)

If A=({:(0,x),(y,0):}) " and " A^(3)+A=0 , then find the relation between x and y (x,y ne 0).

Let's simplify:- (x + y) (x^2 -xy + y^2) + ( x - y) (x^2 + xy + y^2)