`y = x sin x : xy' = y + x sqrt(x^(2) - y^(2))(x ne 0 and x gt y or x lt -y)`

y = Ax : xy' = y (x ne 0)

y = sqrt(a^(2) - x^(2)) x ne (-a, a) : x + y (dy)/(dx) = 0(y ne 0)

x^(y)=y^(x),x=2y

if y + x = 5xy , y - x = -xy

y = sqrt(1 + x^(2)) : y' = (xy)/(1 + x^(2))

The fourth proportional of x - y , x^(2) - y^(2) " and " x^(2) - xy + y^(2) is

Find the value of 8xy (x^(2) +y^(2)) when x +y = sqrt3 , and x -y = sqrt2

Let's simplify:- (x + y) (x^2 -xy + y^2) + ( x - y) (x^2 + xy + y^2)

Statement-1 : Solution of (1 + xsqrt(x^2+y^2) ) dx + y (-1 +sqrt(x^2+y^2)) dy = 0 is x-y^2/2+1/3(x^2 + y^2)^(3/2) +c=0 Statement-2 : Solution of (1 + xy) y dx + (1-xy) x dy = 0 is ln (x/y)-1/(xy)=c

Find the square roots : y+sqrt(y^(2)-x^(2)) (x6^(2)gt y^(2))