xy = log y + C : y' = (y^(2))/(1 - xy)(x...

`xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)`

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x = (sqrt3 + 1)/(sqrt3 - 1) and y = (sqrt3 - 1)/(sqrt3 + 1) . Then (x^2 + xy + y^2)/(x^2 -xy + y^2) is equal to :

The solution of dy/dx =(x^(2)+y^(2)+1)/(2xy) satisfying y(1) = 1 is given by -