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NCERT BANGLISH-DIFFERENTIAL EQUATIONS-EXERCISE - 9.6
- find the general solution : (dy)/(dx) = sin x
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- For each of the differential equation find the general solution(dy)/(d...
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- (dy)/(dx) + (y)/(x) = x^(2)
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- Solve (dy)/(dx) + y = tan x (0 le x lt (pi)/(2))
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- cos^(2)x(dy)/(dx) + y = tan x (o le x le (pi)/(2))
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- Find the Generel Solution x (dy)/(dx) + 2y = x^(2)log x
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- Solvex log x(dy)/(dx) + y = 0
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- Solve (1 + x^(2))dy + 2xy dx = cot x dx (x ne 0)
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- Solve x(dy)/(dx) + y + xy cot x = 0 (x ne 0)
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- SOLVE : y (dy)/(dx) = 1
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- y dx + (x - y^(2))dy = 0
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- Solve(x + 3y^(2))(dy)/(dx) = y ( y rt 0).
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- For each of the differential equations find solution: (dy)/(dx) + ...
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- (1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1
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- (dy)/(dx) - 3y cot x = sin 2x, y = 2 when x = (pi)/(2)
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- Find the equation of a curve passing through the origin given that the...
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- Find the equation of a curve passing through the point (0,2) given tha...
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- The Integrating Factor of the differential equation x (dy)/(dx) - y = ...
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- The Integrating Factor of the differential equation (1 - y^(2))(dx)/(d...
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