Home
Class 12
PHYSICS
Two wires of equal length, one of alumin...

Two wires of equal length, one of aluminium and the other of copper, have the same resistance. Which of the two wires is lighter ? Hence, explain why aluminium wires are preferred for overhead power cables.`(rho _(Al)=2.63xx10^(-8)Omega -m ,P_(Cu)=1.72xx10^(-8)Omega -m`, relative density of Al=2.7,of cu =8.9)

Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NCERT BANGLISH|Exercise EXERCISES|11 Videos
  • ATOMS

    NCERT BANGLISH|Exercise ADDITIONAL EXERCISE|10 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT BANGLISH|Exercise EXERCISES|41 Videos

Similar Questions

Explore conceptually related problems

Two wires of equal length , one of aluminimum and the other of copper have the same resistance.Which of the two wires is lighter? Hence explain why aluminium when are preferred for over head power cables . [rho_(Al)=2.63times10^-8Omega.m,rho_(Ca)=1.72times10^-8Omega.m relative density of Al=2.7 of Cu=8.9].

for two different wires-the length, radius and resistivity are in the ratio 2 : 1 . If one of then has resistance of 10Omega , What will be the resistance of the other?

A wire of unifrom cross section is made from 1g of copper whose resistance is 0.2 Omega Determine the length and cross sectional area of the wire. Given the density of copper =9g.cm^-3 and its resistivity =1.8 times 10^-6 Omega .cm.

A 1 m long metal wire has a cross sectional area of 0.1mm^2 . Find out the resistance of the wire if the resistivity of the metal is 1.8 times 10^-6 Omega.cm.

When an iron wire of diameter 1 cm is copper plated uniformly. Resistance of iron reduces to 1/3 of its original value. Calculate the thickness of copper plating, Resistivities of copper and iron are 1.8 times 10^-6 Omega .cm and 1.98 times 10^-5 Omega .cm respectively.

A potentiometer wire has length 4m and resistance 8Omega the resistance that must be connected in series with the wire and an accumulaterof emf 2 V so as to get a potential gradient 1 mV ,per cm on the wire is

The length of a wire of diameter 0.8 mm is 2.5 m, IF the breaking stress for the material of the wire is 3 times 10^7 kg.m^-2 , then find the load that should be hung from the end of that wire so that it snaps.