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Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

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`2.16eV=3.46xx10^(-19)J`
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Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the cathode, the stopping (cut-off) potential of photo electrons is 0.38 V. Find the work function of the material from which the cathode is made.

The work function (phi) of some metal is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is :

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. Find the work function of the metal and

When radiation of wavelength 4940 Å is incident on a metal surface photoelectricity is generated. For a potential difference 0.6 V between cathode and anode, photocurrent stops. For another incident radiation, the stopping potential changes to 1.1V. Find work function of the metal and wavelength of the second radiation. (h = 6.6 xx 10^(-27) " erg".s, e = 1.6 xx 10^(-19) C)

When a piece of metal is illuminated by monochromatic light of wavelength lamda , the stopping potential for photoelectric current is 2.5V_(0) . If the same surface is illuminated by light of wavelength 1.5 lamda , the stopping potential becomes V_(0) . Find the out the value of threshold wavelength for photoelectric emission.

An electron in the hydrogen atom jumps from excited state n to the Ground state . The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, then the value of n is

Einstein's equation for photoelectric effect is E_("max") = hf - W_(0) , where h = Planck's constant = 6.625 xx 10^(-34) J.s, f = frequency of light incident on metal surface, W_(0) = work function of metal and E_("max") = maximum kinetic energy of the emitted photoelectrons. It is evident that if the frequency f is less than a minimum value f_(0) or if the wavelength lamda is greater than a maximum value lamda_(0) , the value of E_("max") would be negative, which is impossible. Thus for a particular metal surface f_(0) is the threshold frequency and lamda_(0) is the threshold wavelength for photoelectric emssion to take place. Again if the collector plate is ketp at a negative potential with respect to the emitter plate, the velocity of the photoelectrons would decrease. The minimum potential for which the velocity of the speediest electron becoes zero, is known as the stopping potential, the photoelectric effect stops for a potential lower than this. [velocity of light = 3xx 10^(8) m.s^(-1) , mass of an electron m = 9.1 xx 10^(-31) kg , charge of an electron, e = 1.6 xx 10^(-19)C The threshold wavelength of photoelectric effect for a metal surface is 4600 Å . Work function of the metal (in eV) is

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment cann be stoped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

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