The fission properties of ""(94)^(239)Pu...

The fission properties of `""_(94)^(239)Pu` are very similar to those of `""_(92)^(235) U`. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure `""_(94)^(239)Pu` undergo fission?

Text Solution

Verified by Experts

`4.536 xx 10^(26) MeV`.

Topper's Solved these Questions

NUCLEI
NCERT BANGLISH|Exercise ADDITIONAL EXERCISES|8 Videos
NUCLEI
NCERT BANGLISH|Exercise ADDITIONAL EXERCISES|8 Videos
MOVING CHARGES AND MAGNETISM
NCERT BANGLISH|Exercise ADDITIONAL EXERCISES|16 Videos
RAY OPTICS AND OPTICAL INSTRUMENTS
NCERT BANGLISH|Exercise EXERCISES|38 Videos

Similar Questions

Explore conceptually related problems

The fission properties of ._94^239Pu are very similar to those of ._92^235U . The average energy released per fission is 180 MeV . How much energy, in MeV , is released if all the atoms in 1 kg of pure ._94^239Pu undergo fission ?

Calculate the compare the energy released by (a) fusion of 1.0 kg of hydrogen deep within the sun and (b) the fission of 1.0 kg of .^235U in a fission reactor.

In a typical nuclear fission reaction, it was found that there was a loss of mass of 0.2150 u. How much energy in MeV will be released from the reaction ? ( c=3xx10^8 ms^(-1) )

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is (Take leV = 1.6xx10^(-19)J)

A 1000 MW fission reactor consumes half of its fuel in 5 y. How much ._92^235U did it contain initially ? Assume that the reactor was active 80% of the time and all the energy generated arises from the fission of ._92^235U and that this nuclide is consumed by the fission process.

In has been estimated that the total energy radiated by the sun is 3.8xx10^26 J per second. The source of energy of stars is a thermonuclear reaction called nuclear fusion. Fusion reactions are not controlled. It is presumed that the energy of stars is due to two processes called proton-proton cycle and carbon nitrogen cycle. Fusion cannot take place at ordinary temperature. This, hydrogen bomb uses a small fission bomb, which on explosion causes the temperature to rise very high about 10^7 K. We have yet to see how a hydrogen bomb can be used for peaceful life-sustaining purpose. Energy released in the process of fusion is due to mass defect. It is also called Q-value. Q =Deltamc^2 , Deltam= mass defect Answer the following questions based on above passage: Fusion reaction takes place at about:

NCERT BANGLISH-NUCLEI-EXERCISE

Obtain the binding energy (in MeV) of a nitrogen nucleus (""(7)^(14)N)...
Text Solution
|
Obtain the binding energy of the nuclei ""(26)^(56)Fe and ""(83)^(209)...
Text Solution
|
A given coin has a mass of 3.0 g. Calculate the nuclear energy that wo...
Text Solution
|
Write nuclear reaction equations for {:((i) a-"decay of " (88)^(226)...
Text Solution
|
A radioactive isotope has a half-life of T years. How long will it tak...
Text Solution
|
The normal activity of living carbon-containing matter is found to be ...
Text Solution
|
Obtain the amount of ""(27)^(60)Co necessary to provide a radioactive ...
Text Solution
|
The half-life of ""(38)^(90)Sr is 28 years. What is the disintegration...
Text Solution
|
Obtain approximately the ratio of the nuclear radii of the gold isotop...
Text Solution
|
Find the Q-value and the kinetic energy of the emitted a-particle in t...
Text Solution
|
The radionuclide ""^(11)C decays according to ""(6)^(11)C to ""(5)^(...
Text Solution
|
The nucleus ""(10)^(23)Ne decays by beta^(-)– mission. Write down the ...
Text Solution
|
The Q value of a nuclear reaction A + b to C + d is defined by Q =...
Text Solution
|
Suppose, we think of fission of a ""(26)^(56)Fe nucleus into two equal...
Text Solution
|
The fission properties of ""(94)^(239)Pu are very similar to those of ...
Text Solution
|
A 1000 MW fission reactor consumes half of its fuel in 5.00 y. How muc...
Text Solution
|
How long can an electric lamp of 100W be kept glowing by fusion of 2.0...
Text Solution
|
Calculate the height of the potential barrier for a head on collision ...
Text Solution
|
From the relation R = R0A^(1//3), where R0 is a constant and A is the ...
Text Solution
|
For the b+ (positron) emission from a nucleus, there is another compet...
Text Solution
|