Given that sin θ = a/b , then tan θ =...

Given that sin θ = `a/b` , then tan θ =

A

`b/sqrt(b^2 - a^2)`

B

`sqrt(b^2 - a^2)/b`

C

`a/sqrt(b^2 - a^2)`

D

`sqrt(b^2 - a^2)/a`

लिखित उत्तर

Verified by Experts

The correct Answer is:

C

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