If Vectors `vec(A)= cos omega hat(i)+ sin omega hat(j)` and `vec(B)=(cos)(omegat)/(2)hat(i)+(sin)(omegat)/(2)hat(j)`are functions of time. Then the value of `t` at which they are orthogonal to each other is

If Vectors vec(A)= cos omega t hat(i)+ sin omega t hat(j) and vec(B)=(cos)(omegat)/(2)hat(i)+(sin)(omegat)/(2)hat(j) are functions of time. Then the value of t at which they are orthogonal to each other is

If Vectors vec(A)= cos omega t(i)+ sin omega t(j) and vec(B)=cosomegat/(2)hat(i)+sinomegat/(2)hat(j) are functions of time. Then the value of t at which they are orthogonal to each other is

If vectors vec A=cos omega that i+sin omega that j and vec B=cos((omega t)/(2))hat i+sin((omega t)/(2))hat j are functions of time then the value of t at which they are orthogonal to each other is (A) t=(pi)/(w) (B) t=0( C) t=(pi)/(4w)( D) t=(pi)/(2w)

If the vectors given by vec(A) = hat(i) + 2hat(j) + 2hat(k) and vec(B) = hat(i) - hat(j) + n hat(k) are prerpendicular to each other find the value of n .

If vectors vec(a) = 3 hat(i) + hat(j) - 2 hat(k) and vec(b) = hat(i) + lambda(j) - 3 hat (k) are perpendicular to each other , find the value of lambda .

The position vector of a particle is given by vec(r ) = k cos omega hat(i) + k sin omega hat(j) = x hat(i) + yhat(j) , where k and omega are constants and t time. Find the angle between the position vector and the velocity vector. Also determine the trajectory of the particle.

A particle of mass 0.2 kg moves along a path given by the relation : vec(r)=2cos omegat hat(i)+3 sin omegat hat(j) . Then the torque on the particle about the origin is :

A particle of mass 0.2 kg moves along a path given by the relation : vec(r)=2cos omegat hat(i)+3 sin omegat hat(j) . Then he torque on the particle about the origin is :

If vec(A)=2hat(i)+hat(j)+hat(k) and vec(B)=hat(i)+hat(j)+hat(k) are two vectors, then the unit vector is

If vec(A)=2hat(i)+hat(j)+hat(k) and vec(B)=hat(i)+hat(j)+hat(k) are two vectors, then the unit vector is