Equation Of Trajectory

Equations of trajectory of a projectile are x=4 t, y= 3t - 5 t ^(2) , where x and y are in metre and t is in second . Find (i) maximum height attained by the projectille , (ii) horizontal range of the projectile .

The equation of a trajectory of a projectile is y=8x-4x^(2) . The maximum height of the projectile is ?

If y = x - (1)/(2)x^(2) is the equation of a trajectory , find the time of flight.

If y = x - (1)/(2)x^(2) is the equation of a trajectory , find the time of flight.

A particle travels according to the equation x=at^(3),y=bt^(3) . The equation of the trajectory is

A particle travels according to the equation x=at^(3),y=bt^(3) . The equation of the trajectory is

A projectile is fired horizontally with a velocity u, from a height h above the ground. Find the equation of the trajectory .

A projectile is thrown upward with a velocity of V, in a direction making an angle Theta with the horizental. Derive the equation of its trajectory.