The enthalpy of formaion of ammonia gas at 298 K is -46.11 kJ `mol^(-1)`. The equaiton to which this value realtes is

The enthalpy of formation of ammonia gas at 298 K is -46.11 kJ mol^(-1) . The equation to which this value relates is

The enthalpy of formation of ammonia gas at 298 K is -46.11kJ mol^-1 . The equation to which this value related is:

The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_3 rarr N_2 + 3H_2 is

The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g) is :

The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g) is :

The enthalpy of formation of ammonia is -46.0 kJ mol^(-1) .The enthalpy for reaction 2N_2(g)+6H_2(g) rarr 4 NH_3(g) is equal to

The enthalpy of formation of ammonia is -46.0kJ mol^-1. The enthalpy change for the reaction, 2NH_3(g)rarrN_2(g)+3H_2(g) is:

The enthalpy of formation of ammonia is -46.0 kJ mol^(-1) . The enthalpy for the reaction 2N_(2)(g)+6H_(2)(g)to4NH_(3)(g)