According to Graham's law, at a given temperature, the ratio of the rates of diffusion `r_(A)//r_(B)` of gases `A` and `B` is given by

According to Graham's law, at a given temperature the ration of rates of diffusion r_(A)//r_(B) of gases A and B is given by .

According to Graham's law, at a given temperature the ratio of diffusion r_A/r_B of gases A and B is given by (where P and M are pressures and molecular weights of gases A and B respectively)

According to Graham's law at a given temp, the ratio of diffusion r_A//r_B , of gases A and B is given by

When r,P and M represent rate of diffusion, pressure and molecular mass respectively, then the ratio of the rates of diffusion ( r_(A) //r_(B)) of two gases A and B , is given as :

When r, P and M represent rate of diffusion,pressure and molecular mass, respectively, then the ratio of the rates of diffusion ( r_(A) //r_(B)) of two gases A and B , is given as :

When r, p and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (r_A//r_B) of two gases A and B, is given

When r, p and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (r_A r_B) of two gases A and B, is given by?

If the ratio of the rates of diffusion of two gases A and B is 4:1 the ratio of their density is