Calculate the emf of the cell at 298 K
`Sn_((s))|Sn^(2+)(0.05M)||H_((aq))^(+)(0.02M) |H_(2)` 1 atm. Pt
Given that `E_(sn^(2+)//Sn)^(0)=-0.144V`

Write the Nernst equation and calculate the e.m.f. of the following cell at 298K. Sn_((s))|Sn_((0.050M))^(2+)||H^(+)(0.020M)|H_(2)(1atm//Pt) Given E_(Sn//Sn^(2+))^(@)=-0.14V EMF=(E_(H^(+)//1//2H_(2))^(@)-E_(Sn^(2+)//Sn)^(@))-(0.0591V)/(2)"log"([Sn^(2+)])/([H^(+)]^(2)) .

Write the cell reaction and calculate the e.m.f. of the following cell at 298 K : Sn(s) |Sn^(2+) (0.004M)||H^(+) (0.020M) |H_(2)(g) (1 bar )| Pt(s) (Given E_(Sn^(2+)//Sn)^(@) = -0.14V ).

(a) Write the cell reaction and calculate the e.m.f. of the following cell at 298 K : Sn(s) |Sn^(2+) (0.004M)||H^(+) (0.020M) |H_(2)(g) (1 bar )| Pt(s) (Given E_(Sn^(2+)//Sn)^(@) = -0.14V ). (b) Give reasons : (i) On the basis of E^(@) values , O_(2) gas should be liberated at anode but Cl_(2) gas which is liberated in the electrolysis of aqueous NaCl. (ii) Conductivity of CH_(3)COOH decreases on dilution .

Write the Nernst equation and compute the e.m.f. of the following cell at 298K: Sn(s)"|"Sn^(2+)(0.05M)"||"H^(+)(0.02M)"|"H_(2) , 1 atm Pt [Given : E^(Theta)Sn^(2+)//Sn=-0.136V ]

Write Nernst equation and calculate e.m.f of the following cells at 298 K : Sn (s) |Sn^(2+) (0.050 M) ||H^(+) (0.020 M) |H_(2) (1atm) | Pt Given : E_((Sn^(2+) | Sn))^(Theta) = -0.14 V

Write the cell reaction and calculate the emf of the following cell at 298 K. Sn(s)|Sn^(2+)(0.004M)||H^(+)(0.02M)|H_(2)(g)"(1 bar)"|Pt(s). (E_(Sn^(2+)|Sn)=-0.14V)

Write the Nernst equation and emf of the following cells at 298 K. Sn_((s))|Sn_(aq)^2+(0.050M)|H_(aq)^+(0.020 M)|H(2(g))(1 bar)Pt_((s)) (Given E_(Sn^(2+)//Sn)^0 =- 0.136 V)

Write the NERNST equation and calculate e.m.f of following cell at 298 K Sn (s)//Sn^(2 +) (0.050 M) // H^(+) (0.020M)// H_2 (1 atm) Given E^0 Sn (s)//Sn^(2+) =-0.14V