A particle of mass m has momentum p. Its kinetic energy will be

A particle of mass m has momentum p. What is its kinetic energy ?

A particle of mass m has half the kinetic energy of another particle of mass m/2 . If the speed of the heavier particle is increased by 2 ms^(-1) its new kinetic energy becomes equal to t he original kinetic energy of the lighter particle. The ratio of the orighinal speeds of the lighter and heavier particle is

A particle of mass m has half the kinetic energy of another particle of mass m/2 . If the speed of the heavier particle is increased by 2 ms^(-1) its new kinetic energy becomes equal to t he original kinetic energy of the lighter particle. The ratio of the orighinal speeds of the lighter and heavier particle is

The momentum of a body is p and its kinetic energy is E. Its momentum becomes 2p. Its kinetic energy will be

The momentum of a body is p and its kinetic energy is E. Its momentum becomes 2p. Its kinetic energy will be

Find how the momentum of a particle of rest mass m_0 depends on its kinetic energy. Calculate the momentum of a proton whose kinetic energy equals 500MeV .

A particle of mass m and momentum p moves on a smooth horizontal table and collides directly and elastically with a similar particle (of mass m) having momentum -2p . The loss (-) or gain (+) in the kinetic energy of the first particle in the collision is

A particle of mass m and momentum p moves on a smooth horizontal table and collides directly and elastically with a similar particle (of mass m) having momentum -2p . The loss (-) or gain (+) in the kinetic energy of the first particle in the collision is

A particle of mass m , kinetic energy K and momentum p collides head on elastically with another particle of mass 2 m at rest. After collision, : {:(,"Column I",,"Column II",),((A),"Momentum of first particle",(p),3//4 p,),((B),"Momentum of second particle",(q),-K//9,),((C ),"Kinetic energy of first particle",(r ),-p//3,),((D),"Kinetic energy of second particle",(s),(8K)/(9),),(,,(t),"None",):}