A particle describes circular motion with its angular displacement `theta` at anytime `t` is given by `theta=5t-3` radian. If the radius of circular path is `2 m`, find the total acceleration of particle.

A particle performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t is

A particle is performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t is

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.

Angular displacement ( theta ) of a flywheel varies with time as theta=2t+3t^2 radian. The angular acceleration at t=2s is given by

Angular displacement ( theta ) of a flywheel varies with time as theta=2t+3t^2 radian. The angular acceleration at t=2s is given by

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is

A particle starts rotating from rest. Its angular displacement is expressed by the following equation theta=0.025t^(2)-0.1t where theta is in radian and t is in seconds. The angular acceleration of the particle is

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is