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`(dy)/(dx)+ycotx=4xcosecx,x=0" तथा "x=(pi)/(2)" पर "y=0`

(dy)/(dx) + ycotx = 2cos x

Find dy/dx if y= x.cosecx

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

The solution of (dy)/(dx) + y cot x = 4x cosec x , given that y = 0, x = (pi)/(2) is

Solve the following initial value problem: (dy)/(dx)+\ ycotx=4x\ cosec x , \ y(pi/2)=0

Find a particular solution of the differential equation (dy)/(dx)+ycotx=4xcosecx(xne0). Given that y=0 when x=(pi)/(2).

Solve the following differential equation: (dy)/(dx)+y cot x=4x csc x, given that y=0 when x=(pi)/(2)

Solve the following initial value problem: (dy)/(dx)+ycotx=2cosx ,\ y\ (pi/2)=0

Solve the following initial value problem: (dy)/(dx)+ycotx=2cosx ,\ y\ (pi/2)=0