In an electric circuit, potential difference across a lamp is 20 V and current through the lamp is 0.5A. The resistance of the lamp is

In the given circuit calculate potential difference across the lamp and resistor.

An electric lamp is rated 40 W, 100 V. Find the current in the lamp and the resistance of the lamp.

As electric lamp and a conductor of resistance 4 Omega are connected in series to a 6 V battery. The current drawn by the lamp is 0.25 A. Find the resistance of the electric lamp.

As electric lamp and a conductor of resistance 4 Omega are connected in series to a 6 V battery. The current drawn by the lamp is 0.25 A. Find the resistance of the electric lamp.

An electric lamp of resistance 2 Omega and a conductor of resistance 4 Omega are connected to a 6 V Battery as shown in the circuit. Calculate: (a) the totak resistance of the circuit, (b) the current through the circuit, (c) the potential difference across the (i) electric lamp and (ii) conductor, and (d) power of the lamp.

An electrical lamp os marked 240 V - 60 W . What is the resistance of the lamp on incandescent state ?

(a) What is meant by "electric power"? Write the formula for electric power in terms of potential difference and current. (b) The diagram below shows a circuit containing a lamp L, a voltmeter and an ammeter. The voltmeter reading is 3V and the ammeter reading is 0.5A. (i) What is the resistance of the lamp? (ii) What is the power of the lamp? (c) Define kilowatt-hour. How many joules are there in one kilowatt-hour? (d) Calculate the cost of operating a heater of 500 W for 20 hours at the rate of Rs 3.90 per unit.

The voltage across a lamp is (6.0 pm 0.2) volt and current that passes through it is (2.0 pm 0.1) ampere. The power of the lamp in watt is :