Find the equation of the diameter of the circle `x^2+y^2-8x+2y-18=0`, which when produced passes through `(-3,+2)`.

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

Find the equation of the diameter of the circle x^(2) + y^(2) - 4x + 6y + 9 = 0 which passes through the point (1, -2).

Find the equation of the diameter of the circle x ^2 + y ^2 - 14x + 6y + 9 = 0 which passes through the point (2, 1).

Equation of the diameter of the circle x^(2) +y^(2) - 2x + 4y = 0 which passes through the origin is

Equation of that diameter of circle x^(2) + y^(2) - 6x + 2y - 8 = 0 , which passes through origian , is

find the equation of the tangents to the circle x^(2)+y^(2)-2x-4y-20=0 which pass through the point (8,1)

The equation of diameter to the circle x^2+y^2-6x+2y=15 ,which-passes, through (8,-2) is

The equation of the diameter of the circle x^(2)+y^(2)+6 x-4 y-2=0 , passing through the point (2,-3) is