The distance between the point (-1, -5, -10) and the point of intersection of the line `(x-2)/(3)=(y+1)/(4)=(z-2)/(12)` with the plane `x-y+z=5` is -

Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

Find the distance between the point (-1, -5, -10) and the point of intersection of line (x-2)/(3) = (y+1)/(4) = (z-2)/(12) and plane x-y + z =5

The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is

The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is

The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5

Find the distance of the points (-1, -5, -10) form the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5 .