Home
Class 12
CHEMISTRY
Ammonia and oxygen reacts at higher temp...

Ammonia and oxygen reacts at higher temperatures as `4NH_(3)(g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g)` In an experiment, the concentration of NO increases by `1.08 xx 10^(–2)" mol litre"^(–1)` in 3 seconds. Calculate.
(i) rate of reaction.
(ii) rate of disappearance of ammonia
(iii) rate of formation of water.

Promotional Banner

Similar Questions

Explore conceptually related problems

Ammonia and oxygen react at high temperature as: 4NH_(3) (g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g) In an experiment, the rate of formation of NO is 3.6 xx 10^(-3) Ms^(-1) . Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water.

Ammonia and oxygen react at high temperature as : 4 NH_(3(g)) + 5O_2(g)rarr 4NO(g) + 6H_2O_(g) In an experiment, rate of formation of NO(g) is 3.6 xx 10^(-3) mol L^(-1). s^(-1) Calculate :-Rate of formation of water.

Ammonia and oxygen react at high temperature as : 4 NH_(3(g)) + 5O_2(g)rarr 4NO(g) + 6H_2O_(g) In an experiment, rate of formation of NO(g) is 3.6 xx 10^(-3) mol L^(-1). s^(-1) Calculate :- Rate of disappearance of a ammonia.

Ammonia and oxygen react at high temperature as : 4NH_3 (g) +5O_2 (g) to 4 NO(g) +6H_2 O(g) In an experiment, rate of formation of NO is 2.4 xx 10^(-3) mol L^(-) s^(-) . Calculate rate of formation of water.

Ammonia and oxygen react at high temperature as : 4 NH _(3)(g) to 4NO (g) + 6 H _(2) O (g) in an experiment, the rate of formation of NO is 3.6 xx 10 ^(-3) mol L ^(-1) sec ^(-1). Calculate the rate on formation of H _(2)O.