If earth is taken as a sphere of radius 6400 km and mass `6xx10^(24)` kg, what would be the value of g on the surface of earth ?

Assuming the earth of to be a uniform sphere of radius 6400 km and density 5.5 g//c.c. , find the value of g on its surface G=6.66xx10^(-11)Nm^(2)kg^(-2)

Assuming the earth of to be a uniform sphere of radius 6400 kg and density 5.5 g//c.c. , find the value of g on its surface G=6.66xx10^(-11)Nm^(2)kg^(-2)

The earth is a solid sphere of radius 6400 km, the value of acceleration due to gravity at a height 800 km above the surface of the earth is

The mass of the Earth is 6 xx 10^(24) kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth.

The value of 'g' at a depth of 80 km will be ( Radius of earth=6400 km and value of 'g' on the surface of earth is 10 m/s^2 )

An artificial satellite is revolving in a circular orbit at height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km and mass is 6xx10^(24) kg , the orbital velocity is

A satellite of mass 2000 kg is revolving around the earth in a circular orbit of radius 4xx10^(4) km. The gravitational force exerted by the satellite on the earth is ________. [Mass of the earth = 6xx10^(24)kg, G=6.67xx10^(-11)Nm^(2)//kg^(2) ]

Find the gravitational potential energy of a body of mass 10 kg when it is at a height of 6400 km from the earth's surface. [M (earth) = 6xx 10^24 kg, R(earth) =6400 km]